3x^2+4x-2=-20x-23

Solution for 3x^2+4x-2=-20x-23 equation:

3x^2+4x-2=-20x-23

We move all terms to the left:

3x^2+4x-2-(-20x-23)=0

We get rid of parentheses

3x^2+4x+20x+23-2=0

We add all the numbers together, and all the variables

3x^2+24x+21=0

a = 3; b = 24; c = +21;
Δ = b2-4ac
Δ = 242-4·3·21
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-18}{2*3}=\frac{-42}{6}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+18}{2*3}=\frac{-6}{6}
=-1
$